(5+i)/(2+3i), express this in a+ib form
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(5+i)/(2+3i) ×(2-3i)/(2-3i) = 10-5i+2i-3i^2/4-9i^2
10-3i+3/4+9 ( i^2 = -1 )
13-3i/13
1-3i/13
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