5.If ²+12=7 ℎ ∶)+1 ) −1 )2²−22
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Answer:
\boldsymbol xx = 5 units
Explanation:
Given,
In a rectangle the length is (\boldsymbol x + 5)(x+5) units and it's breadth is (\boldsymbol x + 1)(x+1) units
Find the value of \boldsymbol xx if the perimeter is 32 units.
We know that,
Perimeter of a rectangle = 2(l + b)2(l+b)
Where,
ll denotes the length
bb is the breadth of the rectangle.
\therefore \boldsymbol{ 32 = 2[(x + 5) + (x + 1) ]}∴32=2[(x+5)+(x+1)]
Solving for \boldsymbol xx
\implies 32 = 2[(x + 5) + (x + 1) ]⟹32=2[(x+5)+(x+1)]
\implies \dfrac{32}{2} = [x + 5 + x + 1]⟹
2
32
=[x+5+x+1]
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