5) If (28-x) is the mean proportional
the
of (23-x) & (19-x) the find the value of x
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Answer:
(23-x):(28-x):(19-x)
(23-x)/(28-x)=(28-x)/(19-x).
(23-x)×(19-x)=(28-x)×(28-x)
23(19-x)-x(19-x)=28(28-x)-x(28-x)
437-23x-19x+x²=784-28x-28x+x²
-23x-19x+28x+28x+x²-x²=784-437
-42x+56x=347
14x=347
x=347/14
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