5. If Ā = 3i +6j – 2k , the direction of cosines of the
vector Ā are :-
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Answered by
1
Given,
We are given a Ā = 3i +6j – 2k.
To find,
The direction of cosines.
Solution,
- First, we have to calculate the magnitude or resultant of Ā
- The resultant of the vector is calculated as
.
- Similarly, the magnitude or resultant of Ā = 3i +6j – 2k would be,
=
= 7.
- The direction cosine of any given vector can be determined by dividing the corresponding coordinate of a vector by the resultant.
- According to the question, the direction ratios are 3, 6, and -2 respectively.
Hence, The direction of cosines of Ā = 3i +6j – 2k. will be, 3/7, 6/7, and -2/7 (Option b)
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