Question

5. If (4x + 28) and (x-8)° are supplementary angles, find x.​

Answer 1

Answer:

Step-by-step explanation: we know that the sum of supplementary angles

= 180°.

(4X+28) + (X+8)° = 180.°

5X +20 = 180 °.

5X =180 - 20 .

5X = 160°.

X =160/5

X = 32°.

Answer 2

Answer:

$\Large\boxed{X=32}$

Step-by-step explanation:

First, you have to isolate it on one side of the equation. Isolate x on one side of the equation.

The supplementary angles are 180°.

$\displaystyle \mathsf{(4x+28)+(x+8)=180}}}$

$\rightarrow \displaystyle \mathsf{5x+20=180}$

Subtract by 20 from both sides.

$\displaystyle \mathsf{5x+20-20=180-20}$

Solve.

180-20=160

5x=160

Then, divide by 5 from both sides.

$\displaystyle \mathsf{\frac{5x}{5}=\frac{160}{5}}$

Solve.

160/5=32

x=32

$\Rightarrow \Large\boxed{\mathsf{X=32}}$

So, the correct answer is x=32.