Question

5. If (5, 2) is a solution of the equation kx + 4y = 33, find
the value of k.​

Answer 1

k(5)+4(2)=33

5k+8=33

5k=33-8

5k=25

k=25/5

k=5

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Answer 2

$\large{\underline{\underline{\mathfrak{\green{\sf{QUESTION:-}}}}}}$.

• . If (5, 2) is a solution of the equation kx + 4y = 33, find
• the value of k.

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$\large{\underline{\underline{\mathfrak{\sf{SOLUTION:-}}}}}$.

$\large{\underline{\underline{\mathfrak{\sf{GIVEN\:HERE:-}}}}}$.

• equation is (kx + 4y ) = 33

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$\large{\underline{\underline{\mathfrak{\sf{FIND\:HERE:-}}}}}$.

• Value of k when, given here (5,2)

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Now,

If x = 5, and y = 2, solution of this equation

so, satisfies equation for this value .

So , keep value of x and y in this equation .

$\implies\:(k\times5\:+\:4\times2)\:=\:33$

$\implies\:(5k+8)\:=\:33$

$\implies\:(5k)\:=\:(33-8)$

$\implies\:k\:=\cancel{\frac{25}{5}}$

$\implies\bold{\red{\boxed{\boxed{\:k\:=\:5}}}}Ans.$

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