Question

5. If A (3,-10) and B (1,4) are the end points of the diameter AB of a circle, then find the co-
ordinates of the centre of the circle.​

Answer 1

Step-by-step explanation:

given,

A(3,-10) and B(1,4)

are the end points

mid point of the end points is centre

centre=(3+1/2,-10+4/2)

=(4/2,-6/2)

=(2,-3) is tge centre..

Answer 2

Given:

A ( 3 , - 10 ) and B ( 1 , 4 ) are the end points of the diameter AB of a circle.

To find :

The co- ordinates of the center of the circle.

Formula to be used:

Midpoint = $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$

Solution:

Let AB be a diameter of the circle having its centre at C.

The co-ordinates of the center of the circle can be find using the following formula,

Midpoint = $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$

Let,

$x_1 = 3, y_1 = -10\\x_2 = 1, y_2 = 4$

C = $(\frac{3+1}{2},\frac{-10+4}{2} )$

C = $(\frac{4}{2} ,-\frac{6}{2} )$

C = ( 2 , -3 )

Final answer:

The co- ordinates of the center of the circle is ( 2 , - 3) .