Question

5. If a + b +c=0 then (a²/bc+b²/ca+c²/ab)​

Answer 1

Answer:

3

Step-by-step explanation:

a2/bc+b2/ac+c2/ab=(a3+b3+c3)/abc—(1)

a3+b3+c3=(a+b+c)3−3ab(a+b)−3bc(b+c)−3ac(a+c)−6abc—(2)

Since a+b+c=0,b+c=−a,c+a=−b,a+b=−c—(3)

Substitute (3)in(2),

=>a3+b3+c3=03−3ab(−c)−3b(−a)−3ac(−b)−6abc

=>3abc+3abc+3abc−6abc=3abc—(4)

From(1)and (4),(a3+b3+c3)/abc=(3abc)/abc=3