Question

5) If a T.V. set of roting 100 W operates for 6 hrs. per day, find thenumber of units consumed in any leap year.​

Answer 1

Answer:

Firstly multiply power x no. Of days

Then multiply it by 6

Then multiply it by rate of one unit charge

Answer 2

Answer:

Explanation:

Given: Power (P) = 100 W

P = 100

1000

kW = 1

10

kW

Time (t) = 6 × 366 = 2196 hrs

To find: Unit consumed = ?

Formula: H = P × t

Solution: H = P × t

    H = 1

10

× 2196

H = 219.6 kWh

Ans. Number of units consumed is 219.6