Question

5. If A = x - 2, B = y +2 and C = 2y-x, then find the value of
3 ABC​

Answer 1

Step-by-step explanation:

3A×B×C

=3(x-2)×(y+2)×(2y-x)

=3(xy-2y+2x-4)×(2y-x)

=3xy-6y+6x-12×2y-x

Answer 2

The value of 3ABC is $6xy^2-3x^2y+18xy-6x^2-12y^2-12y$

Explanation:

Given that $A=x-2$, $B=y+2$ and $C=2y-x$

We need to determine the value of 3ABC

The value of 3ABC:

To determine the value of 3ABC, let us substitute the values $A=x-2$, $B=y+2$ and $C=2y-x$ , we get,

$3ABC=3[(x-2)(y+2)(2y-x)]$

Let us multiply the terms (x - 2) and (y + 2), we have,

$3ABC=3[(xy+2x-2y-4)(2y-x)]$

Let us multiply the terms within the bracket, we get,

$3ABC=3(2xy^2-x^2y+4xy-2x^2-4y^2+2xy-8y+4y)$

Adding the like terms, we have,

$3ABC=3(2xy^2-x^2y+6xy-2x^2-4y^2-4y)$

Now, we shall multiply the number 3 with each term within the bracket, we get,

$3ABC=6xy^2-3x^2y+18xy-6x^2-12y^2-12y$

Hence, the value of 3ABC is $6xy^2-3x^2y+18xy-6x^2-12y^2-12y$

Learn more:

(1) Of A=10a,B=18b,c=6,find the value of 3abc​

brainly.in/question/14241787

(2) Find the value of a3+b3+c3-3abc if a+b+c=15 and ab+bc+ca=74

brainly.in/question/6119230