5.
If ABC is an equilateral triangle of side a, then its altitude is equal to
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(3) За
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2
Answers
✬ Altitude = √3a/2 ✬
Step-by-step explanation:
Given:
- Measure of side of an equilateral triangle is 'a'.
To Find:
- What is measure of its altitude ?
Solution: Let ∆ABC be an equilateral triangle where
- AB = BC = CA = a
Construction: Draw a perpendicular bisector AD on BC such that
- AD ⟂ BC
- ∠ADC = ∠ADB = 90°
- BD = DC { perpendicular bisects the side BC in two equal halves }
➼ BD = DC = BC/2
➼ BD = DC = a/2
Now , in right angled ∆ADC by using Pythagoras Theorem -
- AD (perpendicular)
- DC (base)
- AC (hypotenuse)
★ H² = Perpendicular² + Base² ★
AC² = AD² + DC²
a² = AD² + (a/2)²
a² = AD² + a²/4
a² – a²/4 = AD²
4a² – a²/4 = AD²
√3a²/4 = AD
√3a/2= AD
Hence, the measure of altitude of equilateral with side a is √3a/2.
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[ Solving through an another method ]
- AC (hypotenuse) = a
- DC (base) = a/2
- AD (perpendicular)
As we know that
➮ Measure of each side of an equilateral triangle is 60°.
So in ∆ADC , using tanθ
★ tanθ = Perpendicular/Base ★
tan60° = AD/DC
√3 = AD/a/2
√3 × a/2 = AD
√3a/2 = AD
Hence, the measure of altitude of equilateral with side a is √3a/2.
Answer:
Given :-
- ABC is an equilateral traingle
- Side = a units
To Find :-
Altitude
Solution :-
Let O be the part of right triangle which divide ABC into 2 equal parts
Now,
Let a perpendicular bisector AO on BC in which,
- AO ⟂ BC
Now,
Since O is dividing into both parts,
So,
∠AOC = ∠AOB = 90°
Now,
BO = OC = BC/2
BO = OC = a/2
By using Pythagoras Theorem
H² = P² + B²
H is the Hypotenuse
P is the Perpendicular
B is the Base
AC² = AO² + OC²
Now,
- AC = a
- AO = AO
- OC = a/2
a² = AO² + a/2²
a² = AO² + a × a/2 × 2
a² = AO² + a²/4
AO² = a² - a²/4
AO² = 4a² - a²/4
AO² = 3a²/4
AO² = √3a/2