Question

5.
If area of a parallelogram and its base is given by the values of x and y respectively obtained
from equations x + 5y = 50 and 2x - y = 20, then find the altitude of the parallelogram.​

Answer 1

$\huge\bold\red {Answer: }$

Since ABCD is a parallelogram, AB∥DC and AD∥BC

Now, AB∥DC and transversal BD intersects them.

∴∠ABD=∠BDC since alternate angles are equal.

⇒10x=60

∘

⇒x=

10

60

∘

=6

∘

And, AD∥BC and transversal BD intersects them.

∴∠DBC=∠ADB

⇒4y=28

∘

⇒y=

4

28

∘

=7∘

Answer 2

Answer:

Use linear equation in 2 variable

x+5y=50

x=50-5y.....(1)

now, 2x-y=20

2(50-5y)-y=20

y=80/11

substitute in (1)

x=150/11

ar=x,base=y

height= ar/base

=150/11*11/80

=15/8