Question

5.
If cos A = √3/2,0° <A < 90°, then A is equal to
(A)√3/2
(B)30°
(C)2√3
(d) -12
​

Answer 1

Answer:

sin x ∙ cos x = 0 and then the inequality . sin x ∙ cos x > 0 on the interval 0 x < 2. The inequality has no solution when sin x or cos x take the value 0. This happens at intervals of 90°. The solutions of the equation sin x ∙ cos x = 0 on the interval 0 x < 2 are therefore 0, /2, and 3 /2 (0°, 90°, 180° and 270°

Step-by-step explanation: