Question

5. If each side of a cube is increased by 50%, find the percentage increase in its surface area.​

Answer 1

Answer:

Percentage increase in its surface area $= 125$%

Step-by-step explanation:

Let's assume that the initial length of each side of the cube is x.

The surface area is 6 times $x^2$ $= 6x^2$

Now, if each side is increased by 50%, the new length will be:

$x + \frac{50}{100} .x$ $= 1.5x$

The new surface area will be 6 times $(1.5x)^2$ = 6 times $2.25x^2 = 13.5x^2$

Therefore, increase in surface area $= 13.5x^2 - 6 x^2 = 7.5x^2$

Percentage increase in its surface area $\frac{7.5x^2}{6x^2} . 100$% $= 125$%