Question

5. If k-1, k + 3 and 3k - 1are in AP, then
find the value of k.
CBSE 2011​

Answer 1

Answer:

k-1,k+3,3k-1 are in A.P

By finding the common difference i.e a3-a2

a3=3k-1,a2=k+3

3k-1-(k+3)

3k-1-k-3

2k-4=0

2k=4

k=2

Step-by-step explanation:

I hope this answer may help you