Question

5 If m and n are the roots of the equation x2 - p(x + 1) - c = 0,yy find the value of (m + 1)(n + 1).​

Answer 1

i don't know,sorry next time.

Answer 2

Step-by-step explanation:

We know that if m and n are the roots of a quadratic equation ax2+bx+c=0, the sum of the roots is m+n= −b/a and the product of the roots is mn= c/a.

Here, the given quadratic equation x2−6x+2=0 is in the form ax2+bx+c=0 where a=1,b=−6 and c=2.

The sum of the roots is:

m+n= −b/a=−(−6)/1=6

The product of the roots is ac that is:

mn= c/a = 2/1 =2 

Now, 

m3n2+n3m2=m2n2(m+n)=(mn)2(m+n)=22×6=4×6=24

Hence, the value of m3