Question

5.If one zero of the polynomial 3x2-8x+2k+1 is seven times the other, then find the

value of k​

Answer 1

Step-by-step explanation:

First zero = x

second zero = 7x

x + 7x = 8/3

8x = 8/3

x = 1/3

first zero x = 1/3

Second zero 7x = 7/3

x*7x = (2k+1)/3

1/3 * 7/3 = (2k+1)/3

7/9 = (2k+1)/3

9(2k+1) = 21

18k + 9 = 21

18k = 12

k = 12/18 = 2/3

Answer 2

Answer:

Step-by-step explanation:

First zero = x

second zero = 7x

x + 7x = 8/3

8x = 8/3

x = 1/3

first zero x = 1/3

Second zero 7x = 7/3

x*7x = (2k+1)/3

1/3 * 7/3 = (2k+1)/3

7/9 = (2k+1)/3

9(2k+1) = 21

18k + 9 = 21

18k = 12

k = 12/18 = 2/3