5. If one zero of the quadratic
polynomial 2x²+kx-15 is 3, then
the other zero is
Answers
Answered by
5
Answer:
-5/2
Step-by-step explanation:
let two roots be p and q.
p=3,we need to find q
sum of roots= p+q =-(b/a).
3+q=(-k/2).............(1)
product of roots=p.q=c/a
3.q=-15/2
q=-5/2
from (1)
1/2=-k/2
k=-1
q is other root =-5/2
Answered by
4
Solution:
f(x) = 2x^2 + kx - 15
d(x) = x - 3 , x = 3
f(x) = 2x^2 + kx - 15
f(3) = 2(3)^2 + k(3) - 15
= 18 + 3k - 15
= 3k + 3
-3k = 3
k = -1
Therefore, 2x^2 + kx - 15 = 2x^2 - x - 15
Factor out 2x^2 - x - 15 = (x - 3) (2x + 5)
(x - 3) (2x + 5) = 0
x = 3 and x = -5/2
Hope this will be helpful.
f(x) = 2x^2 + kx - 15
d(x) = x - 3 , x = 3
f(x) = 2x^2 + kx - 15
f(3) = 2(3)^2 + k(3) - 15
= 18 + 3k - 15
= 3k + 3
-3k = 3
k = -1
Therefore, 2x^2 + kx - 15 = 2x^2 - x - 15
Factor out 2x^2 - x - 15 = (x - 3) (2x + 5)
(x - 3) (2x + 5) = 0
x = 3 and x = -5/2
Hope this will be helpful.
Similar questions