5. If P ( 1, 2) Q( 4,6)R(5,7)S (a,b) are the vertices of a parallelogram PQRS. Find the value of " a " and "b"*
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Answer:
llgm diagonals bisect each other at mid pt
Step-by-step explanation:
then PS=QR
(1+a/2,2+b/2)=(5+4/2,7+6/2)
(1+a/2,2+b/2)=(9/2,13/2)
i.e 1+a/2=9/2,2+b/2=13/2
a/2=9-2/2,b/2=13-4/2
a=9,b=9
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