5. If p(x) = x2 – 4x + 3, evaluate: p(2) – p(-1) + p(1)
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P(x) =x^2-4x+3
P(2)=(2)^2-4(2)+3
P(2)=(4)-4(2)+3
P(2)=4-8+3
P(2)=-1
P(-1)=(-1)^2-4(-1)+3
P(-1)=1+4+3
P(-1)=8
P(1)=(1)^2-4(1)+3
P(1)=1-4+3
P(1)=0
P(2)-P(-1)+p(1)
=-1-8+1
=-6
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