Question

5. If p(x) = x2 - 4x + 3 then, find the value of
p (2)–p (-1) + P(+)

Answer 1

Step-by-step explanation:

Given :

$p(x) = {x}^{2} - 4x + 3$

Therefore,

$p(2) = {2}^{2} - 4 \times 2 + 3 \\ => p(2) = \: 4 - 8 + 3 \: = - 1$

$p( - 1) \: = \: {( - 1)}^{2} + 4 \times ( - 1) + 3 \\ => p( - 1) \: = 1 - 4 + 3 = 0$

$p(1) = {1}^{2} + 4 \times 1 + 3 = 8$

Therefore,

$p(2) + p( - 1) + p(1) = - 1 + 0 + 8 = 7$

Hence, the answer is 7.