Question

5)
If roots of quadratic equation 3x2 - kx + k
= 0 are real and equal, then the value of k
is ....
(1) 3 (2) 6 (3) 9 (4) 12​

Answer 1

Answer:

3×2-kx+k<=0

6_kx+k<=0

Answer 2

Answer:

b^2 - 4ac=0

(-k)^2 - 4(3)(k) = 0

k^2 - 12k=0

k( k-12)= 0

hence k=0

or

k= 12

FROM THE OPTIONS GIVEN, THE VALUE OF k= 12

HOPE THIS HELPS YOU...