Question

5. If sec 4A = cosec (A - 20°), where 4A is an acute angle, find the value of A​

Answer 1

Hi !

Solution :- Sec4A = cosec( A - 20° )

sec4A = sec(90° - A + 20)

4A = 110-A

5A = 110°

A = 21°

Answer !

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Hope it's helpful !

Answer 2

$\sec(4a) = \cosec(a - 20) \\ \\ \cosec(90 - 4a) = \cosec(a - 20) \\ \\ (90 - 4a) = (a - 20) \\ \\ 90 + 20 = a - 4a \\ \\ 5a = 110 \\ \\ a = \frac{110}{5} \\ \\ a = 22 \: answer \\ \\ \\ {\huge{\boxed{\mathbb{\purple{Stay \: strong}}}}}$