Question

5. If seco+tano =31, then tano-seco value is how much?​

Answer 1

Answer

-1/31

$\sf\rule{200}2$

Given

sec∅ + tan∅ = 31

To find

The value of

tan∅ - sec∅

Solution

We know that,

sec²∅ - tan²∅ = 1

It can be factorised as,

(sec∅ - tan∅)(sec∅ + tan∅) = 1

(using, a² - b² = (a + b)(a - b))

We know that sec∅ + tan∅ = 31

So,

(sec∅ - tan∅)(31) = 1

→ sec∅ - tan∅ = 1/31

Multiply with (- 1) on both sides

→ (- 1)(sec∅ - tan∅) = (- 1/31)

→ tan∅ - sec∅ = -1/31

Answer 2

Answer:

HEY Buddy here's ur answer

Given

sec∅ + tan∅ = 31

To find

The value of

tan∅ - sec∅

Solution

We know that,

sec²∅ - tan²∅ = 1

It can be factorised as,

(sec∅ - tan∅)(sec∅ + tan∅) = 1

(using, a² - b² = (a + b)(a - b))

We know that sec∅ + tan∅ = 31

So,

(sec∅ - tan∅)(31) = 1

→ sec∅ - tan∅ = 1/31

Multiply with (- 1) on both sides

→ (- 1)(sec∅ - tan∅) = (- 1/31)

→ tan∅ - sec∅ = -1/31