5. if sin theta=12/13 and theta lies in 2 quadrant, then
find the value
of
8 tan theta-✓5 sec theta
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4
Answer:
1/5 * ( 96- 13√5)
Step-by-step explanation:
sin A = 12/13 = p/h ,b = √(13^-12^2) = 5
8tanA - √5secA = 8× 12/5 - √5× 13/5
= 1/5 *( 96 - 13√5)
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