Question

5. If tan (A+B) = 13 and tan (A - B) = 13:0° <A+B<90°; A>B, find A and B.
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Answer 1

Answer:

A≈85.6°

B=0°

Step-by-step explanation:

tan(A+B)=13

and tan( A-B)=13

0<A+B<90°

So A and B both are acute

tan (A+B) = 13 =tan (A - B)

So A+B=A-B

2B=0, B=0

Thus Tan(A+0)=13

tanA=13

A= tan^-1(13)

=0.85.6 degree