Question

5. If the bond enthalpy of Oz, N, and H, are 498 kJ mol',946 kJ mol' and 435.8 kJ mol'respectively. Choose the correct order
of decreasing bond strength
2) H.> Ny> O2
b) N2> 0,> H2
c) 0,>H>N
d) H> 0,> N,​

Answer 1

Answer:

this is the answer-

Explanation:

H2>N2>O2

N2>O2>H2

O2>H2>N2

H2>O2>N2

Solution :

(b) Larger the bond dissociation enthalpy, stronger will be the bond in the molecule.So, N2946kJmol−1>O2498kJmol−1>H2435.8kJmol−1