5. If the distance between two objects decreases
to 25%, then to what percent does the force of
gravitation change?
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Answers
We know that,
The formula of force of gravity, F = \frac{Gm_1m_2}{d^2}
Where is theG is the Gravitational constant.
m_1 and m_2 is the masses of the two bodies 1 and 2 respectively.
d is the distance of the of the two bodies.
Then,
If the the distance between two bodies is increased by 25%,
So,
d' is the distance of the of the two bodies after the distance increased by 25%,
d' = d + \frac{25}{100} \times d
= d + \frac{1d}{4}
= \frac{5d}{4}
Then,
The force of gravity after the distance increased by 25%, F' = \frac{Gm_1m_2}{d'^2}
F' =\frac{Gm_1m_2}{d'^2}
= \frac{Gm_1m_2}{\frac{5d}{4}^2}
= \frac{16}{25} \frac{Gm_1m_2}{d^2}
F'= \frac{16}{25} F
The change in gravitational force \Delta F(%) = \frac{F' - F}{F} \times 100
= \frac{\frac{16}{25} F - F}{F} \times 100
= (\frac{16}{25} - 1 ) \times 100
= \frac{16 - 25}{25} \times 100
= (-9) \times 4
\Delta F = -36%
Here, the (-) negative sign indicates the decreasing of the gravitational force.
Hence, the % change in gravitational force is decreases by 36%.
To know more:
How does the force of gravitation between two objects change when the distance between them is doubled
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