5. If the enthalpy change for the transition of liquid
water to steam is 30 kJ mol1 at 27°C, the entropy
change for the process would be
[AIPMT (Prelims)-2011]
(1) 100 J mol-1 K-1 (2) 10 J mol-1 K-1
(3) 1.0 J mol-1 K-1 (4) 0.1 J mol-1 K-1
Answers
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Answer:
(1) 100J/mol/K
Explanation:
dQ= 30kJ/mol = 30000J/mol
t = 27°C ; T = 27 + 273 = 300K
dS = dQ/T
dS = 30000/300
dS = 100J/mol/K
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