Question

5. If the equation x^2-bx + 1 = 0 has two distinct roots then​

Answer 1

Answer:

(1) If the equation has exactly one real root, then d = 0

a^2 - 4 = 0

a^2 = 4

|a| = 2

(2) If the equation has two real roots, then d > 0

a^2 - 4 > 0

a^2 > 4

|a| > 2

(3) If the equation has two complex-valued roots, then d < 0

a^2 - 4 < 0

a^2 < 4

|a| < 2

Answer 2

hey mate your answer

x+1)(x−2)+x=0⇒x

2

−x+x=0⇒x

2

−2=0

D=b

2

−4ac=0−4(1)(−2)=8>0

∴ Given equation has two distinct real roots

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