5-If the point D and E are situated on the sides AB and AC respectively in a triangle ABC. Such that
BC = CE, then prove that ∆ABC is an isosceles triangle .
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By basic proportionality property,
⇒ DBAD=ECAE
By adding 1 on both sides,
⇒ DBAD+1=ECAE+1
⇒ DBAD+DB=ECAE+EC
⇒ DBAB=CEAC
It is given that, DE∥BC and BD=EC
⇒ BDAB=BDAC [ CE=BD ]
⇒ AB=AC
∴ △ABC is isosceles triangle.
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