Question

5. If the polynomials 2x2 + ax² + 3x - 5 and x3 + x2 - 4x + a leave the same remainder
when divided by x-2, find the value of a.​

Answer 1

Answer:

So that,

f(2) = g(2)

2x³+ax²+3x-5 = x³+x²-4x+a

2(2)³+a(2)²+3(2)-5 = 2³+2²-4(2)+a

2(8)+a(4)+6-5 = 8+4-8+a

16+4a+1 = 4+a

17+4a = 4+a

4a-a = 4-17

3a = -13

a = -13/3.