Math, asked by khushii35, 5 months ago

5. If the roots of the equations (a-b) x^ 2 + (b - c) * x + (a - b) = 0 are real and equal, then which of the following is true? (a) 2b = a + c (c) 2c = a + b (b) 2a = b + c (d) 2b = a - c​

Answers

Answered by emily22
1

Answer:

option (b)

Step-by-step explanation:

b^2 - 4ac = 0 ( roots are real and equal )

here,

a = (a - b), b = (b - c), c = (a - b)

(b - c) ^2 - 4(a - b) (a - b) = 0

(b - c) ^2 - (2(a - b)) ^2 = 0

( b-c + 2(a - b) )( b-c -2(a - b)) = 0

(2a - c - b)(3b - c - 2a) =0

2a - c - b = 0

2a = b + c ......... option (b)

3b - c - 2a = 0

3b = 2a + c

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