Question

5) If the sum of three consecutive odd numbers is 33 then what are the numbers?

The first number =

Second number = ----

The third number =

---- + ----- + ---- = 33

--- + ---- = 33

x = ----

Numbers are......​

Answer 1

Step-by-step explanation:

The first number = x

Second number = x+2

The third number =x+4

x+x+2+x+4= 33

3x+6= 33

3x= 33-6

3x =27

x=27/3

x=9

Numbers are......x=9,

x+2=9+2=11,

x+4=9+4=13

Answer 2

Answer:

Three consecutive numbers when added = 33

Let the first number be x

So, 1st number = x

      2nd number = (x + 1)

      3rd number = (x+2)

Forming an equation, we get,

1st number + 2nd number + 3rd number = 33

= x + (x + 1) + (x + 2) = 33

= 3x + 3 = 33

= 3x = 33 - 3

= 3x = 30

= x = $\frac{30}{3}$

= x = 10

Therefore, 1st number = x = 10

                   2nd number = (x + 1) = 10 + 1 = 11

                   3rd number = (x + 2) = 10 + 2 = 12

Therefore, 1st number = 10

                   2nd number = 11

                   3rd number = 12

To verify, 10 + 11 + 12 = 33

Hence found...

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