Question

5. If the velocity of a train which starts from rest is 72 km/h (20 m/s)
after 5 minute, find out its acceleration and the distance travelled
by the train in this time.​

Answer 1

Explanation:

v=u+at

u=0

20m/s=a*300seconds

a=1/15 m/s²

v²=2as

u=0

400=2/15*s

400*15/2=s

s=3000m