Question

5. If the velocity of a train which starts from rest is 72 km/h (20 m/s)after 5 minute, find out its acceleration and the distance travelledby the train in this time.​

Answer 1

Explanation:

5min=5×60=300s

a=change in velocity/time

a=20/300

1/15

s=ut +1/2at2

s=1/2×1/15×300×300

s=3000metre..