Question

5.
If the velocity of a train which starts from rest is 72 km/h (20 m/s)
after 5 minute, find out its acceleration and the distance travelled by the train in this time.
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Answer 1

Explanation:

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Answer 2

Answer:

i) u=0, v= 72 km/h = 72×5/18=20 m/s

t= 5 min = 5×60=300seconds

a=v-u/t= 20-0/300=1/15m/s²

ii) 2 as=v²-u²,u=0

s=v²/2a= 20²/2×1/15=3000m=3 km