Math, asked by ricky82, 8 months ago

5
If triangle ABC is right angled at C, then the value of sec (A+B) is
a) 0
b) 1
d) not defined​

Answers

Answered by gjaynir0508
1

Answer:

it is equal to sec90°=not defined

so option (c) is the answer

Step-by-step explanation:

As triangle ABC is right angled at C ,by angle sum property of triangle sum of angles A and B should be 90°.

because

A+B+C=180°

A+B+90°=180°

A+B=180°-90°

A+B=90°

and so

sec(A+B)=sec90°=not defined

hope this helps you

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