Question

5. If x+1 is a factor of the given polynomial, then the value of k is
$2 {x}^{2} + kx +1$
​

Answer 1

Answer:

-2

Step-by-step explanation:

x+1=0

x=-1

p(-1) = 2(-1)^2 + k(-1) + 1

= 2+k =0

k=-2

Answer 2

Answer:

k=3

Step-by-step explanation:

$Letf(x)= 2x^2+kx+1\\x+1 is a factor.So,\\x+1=0\\or, x=-1\\Using remainder theorem,\\f(-1)= 2*(-1)^2 + k*(-1) +1\\or, 0 = 2 -k +1\\or, k=3$