5. If x= -2 is the root of the equation √2(x+p)=0 and is also the zero of the
polynomial px²+kx+3 ,then find the value of k.
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Answer:
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Step-by-step explanation:
if x=-2
then take -2 in place of x
√2(-2+p)=0
-2√2+√2p=0
√2p=2√2
p=2√2/√2
then √2 will cut √2
then p=2
px^2+kx+3
substitute 2 in place of p
and -2 in place of x
2×(-2)^2+k×-2+3=0
2×2-2k+3=0
4-2k+3=0
7-2k=0
-2k=-7
k=-7/-2
k=7/2 or k=3.5
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