Math, asked by shain21, 1 year ago

5. If x= -2 is the root of the equation √2(x+p)=0 and is also the zero of the
polynomial px²+kx+3 ,then find the value of k.​

Answers

Answered by Lakshyaraj12345678
4

Answer:

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Step-by-step explanation:

if x=-2

then take -2 in place of x

√2(-2+p)=0

-2√2+√2p=0

√2p=2√2

p=2√2/√2

then √2 will cut √2

then p=2

px^2+kx+3

substitute 2 in place of p

and -2 in place of x

2×(-2)^2+k×-2+3=0

2×2-2k+3=0

4-2k+3=0

7-2k=0

-2k=-7

k=-7/-2

k=7/2 or k=3.5

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