Question

5. If x = 6 and y = -8, find the value of x2 + y2 = 1

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Answer 1

Answer:

4/1

Step-by-step explanation:

• (6)2 + (-8)2=1

• 12 + (-16) =1

•12-16=1

•4=1

•4/1

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Answer 2

Step-by-step explanation:

If x + y = 2 and x^2 + y^2 = 2, what is the value of xy ?

If x + y = 2 and x^2 + y^2 = 2, what is the value of xy ?A. –2

If x + y = 2 and x^2 + y^2 = 2, what is the value of xy ?A. –2B. –1

If x + y = 2 and x^2 + y^2 = 2, what is the value of xy ?A. –2B. –1C. 0

If x + y = 2 and x^2 + y^2 = 2, what is the value of xy ?A. –2B. –1C. 0D. 1

If x + y = 2 and x^2 + y^2 = 2, what is the value of xy ?A. –2B. –1C. 0D. 1E. 2

If x + y = 2 and x^2 + y^2 = 2, what is the value of xy ?A. –2B. –1C. 0D. 1E. 2(x+y)^2 = x^2+y^2+2xy

If x + y = 2 and x^2 + y^2 = 2, what is the value of xy ?A. –2B. –1C. 0D. 1E. 2(x+y)^2 = x^2+y^2+2xy4=2+2xy

If x + y = 2 and x^2 + y^2 = 2, what is the value of xy ?A. –2B. –1C. 0D. 1E. 2(x+y)^2 = x^2+y^2+2xy4=2+2xyxy=1

If x + y = 2 and x^2 + y^2 = 2, what is the value of xy ?A. –2B. –1C. 0D. 1E. 2(x+y)^2 = x^2+y^2+2xy4=2+2xyxy=1D

If x + y = 2 and x^2 + y^2 = 2, what is the value of xy ?A. –2B. –1C. 0D. 1E. 2(x+y)^2 = x^2+y^2+2xy4=2+2xyxy=1D_________________

If x + y = 2 and x^2 + y^2 = 2, what is the value of xy ?A. –2B. –1C. 0D. 1E. 2(x+y)^2 = x^2+y^2+2xy4=2+2xyxy=1D_________________Cheers,