5.
IfAROMA=24, GRAND=22, KWALITY
(a) 40
(b) 62
(c) 55.5
(d). 50.5
Answers
Answer:
for aroma a=1, r =18 o =15 m = 13 ,a=1 so 1+18+15+13+1/2==48/2=24
like wise grand = 7+18+1+14+4/2==44/2=22
like wise kwality ==11+23+1+12+9+20+25/2==101/2==50.5
so solution is (d)50.5
Answer:
KWALITY = 50.5 (d)
Given:
AROMA = 24, GRAND = 22
To find :
Value of KWALITY according to the given values.
Solution:
Coding-Decoding is a process of encrypting or decrypting any word, letter, or sentence in a set pattern or code based on some set of rules. Coding and Decoding of information are done with various rules or patterns.
Here the letters are coded according to sum of count of the given letters and then divided by two :
A-1, B-2, C-3, D-4, E-5, F-6, G-7, H-8, I-9, J-10, K-11, L-12, M-13, N-14, O-15, P-16, Q-17, R-18, S-19, T-20, U-21, V-22, W-23, X-24, Y-25, Z-26.
AROMA - A(1) + R (18) + O(15) + M(13) + A(1)
2
= 1 + 18 + 15 + 13 + 1
=48 /2 = 24
GRAND - G(7) + R(18) + A(1) + N(14) + D(4)
2
= 7 + 18 + 1 + 14 + 4
= 44 / 2 = 22
KWALITY - K(11) + W(23) + A(1) + L(12) + I(9) +
T(20) + Y(25)
2
= 11 + 23 + 1 + 12 + 9 + 20 + 25
= 101/2 = 50.5
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