Question

5. Ifx+y+z=6, x-y+z=2, 2x+y-z-1, then value of xyz is?​

Answer 1

Answer:

By subtracting x+y+z=6 from x-y+z=2 we get y=2.multiply x-y+z=4 with 2 and subtract it from 2x+y-z=1 we get z=3.On substituting y and z values in any of the equation we get x=1 then xyz=6