Question

5. In A ABC, B = 70° and angle C = 80°. The bisector of
angle A intersects BC at D, then find angle ADB and ADC.​

Answer 1

refer the given attachment.

Answer 2

Answer:

Therefore, angle ADB = 110° and angle ADC = 125°.

Step-by-step explanation:

First, let's find angle A:

Angle A + angle B + angle C = 180° (Sum of angles in a triangle)

Angle A + 70° + 80° = 180°

Angle A = 30°

Now, we can find angle ADB:

Angle ADB = 180° - angle ABD - angle BAD (Angle sum property of a triangle)

Since AD is the bisector of angle A, we know that angle ABD = angle A/2 and angle BAD = angle B/2 = 35°

So, Angle ADB = 180° - 30°/2 - 35° = 110°

Similarly, we can find angle ADC:

Angle ADC = 180° - angle ACD - angle CAD (Angle sum property of a triangle)

Since AD is the bisector of angle A, we know that angle ACD = angle C/2 = 40° and angle CAD = angle A/2 = 15°

So, Angle ADC = 180° - 40° - 15° = 125°

Therefore, angle ADB = 110° and angle ADC = 125°.

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