5: In A ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine:(i) sin
A, cos A (ii) sin 0, cos *
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Answer:
(i)7/25,24/25 (ii)24/25,7/25
Step-by-step explanation:
In triangle ABC,
angle B = 90°
=>AB²+BC²=AC²(Pythagoras Theorem)
=>(24 cm)²+(7 cm)²=AC²
=>576 cm²+49 cm²=AC²
=>AC²=625 cm²
=>AC=√625 cm²
=>AC=25 cm
(i) sin A = perpendicular/hypotenuse
= BC/AC
= 7 cm/25 cm
= 7/25
cos A = base/hypotenuse
= 24 cm/25 cm
= 24/25
(ii) sin C = AB/BC
= 24 cm/25 cm
= 24/25
cos C = BC/AC
= 7 cm/25 cm
= 7/25
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