Question

(5) In a basket there are 10 tomatoes. The weight of each of these tomatoes in grams is as

follows 60, 70, 90, 95, 50, 65, 70, 80, 85, 95.

Find the median of the weights of tomatoes.

Answer 1

To find the median of the given ungrouped data,

Firstly, Arrange the given data into ascending order --

50 < 60 < 65 < 70 < 70 < 80 < 85 < 90 < 95 < 95

Here, Total number of observations (n) = 10

As 10 is a even term,

Therefore,

$median \: = \frac{ (\frac{n}{2} )th \: term +( \frac{n}{2} + 1)th \: term}{2} \\ \\ = > \frac{ (\frac{10}{2} )th \: term+ ( \frac{10}{2} + 1) th \: term}{2} \\ \\ = > reduce \: the \: fraction \\ \\ \frac{5th \: term + \: 5 + 1th \: term }{2} \\ \\ \frac{5th \: term + 6th \: term}{2} \\ \\ 5th \: term = 70 \\ \\ 6th \: term = 80 \\ \\ \frac{70 + 80}{2} \\ \\ \frac{150}{2} \\ \\ 75 \: is \: the \: median$

Answer 2

Answer:

75 Grams

Step-by-step explanation:

We have been given the data:-

60, 70, 90, 95, 50, 65, 70, 80, 85, 95

Arrange it in ascending order:-

50, 60, 65, 70, 70, 80, 85, 90, 95, 95

The total number of observations (n) here is 10.

10 is an even number.

We would be using the formula:-

$\frac{(\frac{n}{2})th term + (\frac{n}{2}+1) th term}{2}$

Substitute the value of 'n' :-

= $\frac{(\frac{10}{2})th term + (\frac{10}{2}+1) th term}{2}$

= $\frac{5th+6th}{2}$

Replace the values of 5th and 6th term:-

= $\frac{70+80}{2}$

= $\frac{150}{2}$

= 75

So, the Median of the data is 75 grams !