Question

5. In a circle with centre P. AB is a diameter and
ABCD is a cyclic quadrilateral. If angle ADC = 150,
then find BAC.​

Answer 1

Answer:

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Answer 2

Answer:

Ina cyclic quadrilateral ABCD

angle ADC =150

now, AB ||ar to DC

so, ADC+BAC=180

150 +BAC=180

BAC = 30°