Question

5. In a class of 40 students, each one plays either Tennis or Badminton or both. If 28 play Tennis and
26 play Badminton, find
(i) how many play both the games;​

Answer 1

Answer:

14

Step-by-step explanation:

see I can't understand the but what's is my

explanation I am giving to you dear

Answer 2

Step-by-step explanation:

It is given that out of 60 students, 5 students play none of the sports so the no of students playing atleast one game (cricket or football) is 60–5=55.

Using the Venn diagrams, it can be said that

n(A∪B) =n(A) +n(B) - n(A∩B)

where ,

n(A) is the number of students playing cricket =45

n(B) is the number of students playing football =30

n(A∪B) is the number of students playing atleast cricket or football = 55 (as said above)

n(A∩B) is number of students playing both cricket and football which we should find out . So using above formula

55=45+30-n(A∩B),

n(A∩B)=45+30–55=20.

So the number of students playing both cricket and football is 20