Math, asked by azariahlifehouse12, 3 days ago

(5) In a co-operative society, the number of men is thrice the number of women. 29 women and 16 men more joined the society and now the number of men is double the number of women. How many women were there in the society at first?​

Answers

Answered by raopranaya24
4

Step-by-step explanation:

let the number of women be x

now, number of men is 3x.

ATQ, number of women = x + 29

number of men = 3x + 16

Now, (3x + 16) = 2(x + 29)

= 3x + 16 = 2x + 58

= 3x - 2x = 58 - 16

= x = 42

x = 42

therefore the number of women in the society at first was 42.

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Answered by pavnishhema1
0

Answer:

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