5. In a group of 100 birds, 85 had a long beak, 45 had
grey feathers and 38 had both a long beak and
grey feathers. How many did not have a long beak
and did not have grey feathers?
Answers
Answered by
7
YOUR ANSWER:
No. of birds = 100
No. of birds having a long beak = 85
No. of birds having grey feathers = 45
No. of birds having both a long beak and grey feathers = 38
So, no. of birds not having both a long beak and grey feathers = (85+45) - 38 = 130 - 38
=>92
Therefore, no. of birds not having a long beak = 92-85
=> 7
And no. of birds not having grey feathers = 92 - 45
=> 27
Hope it works out... ^_^
Answered by
1
If we add this so and will come 120 but the group of birds is 100
Check your question again
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